If the area of an equilateral triangle is 81 root 3 cm2 , find its perimeter
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Answered by
877
given that
we know that area is √3/4 a²
area of the equilateral triangle = 81√3
√3/4 a² = 81√3
1/4 a² = 81
a² = 81(4)
a² = 324
a = 18cm
then the perimeter of the equilateral triangle = 3×a
= 3×18
=54cm.
we know that area is √3/4 a²
area of the equilateral triangle = 81√3
√3/4 a² = 81√3
1/4 a² = 81
a² = 81(4)
a² = 324
a = 18cm
then the perimeter of the equilateral triangle = 3×a
= 3×18
=54cm.
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Answered by
230
Area of equilateral triangle = root 3 a^2
81 root 3 = root 3/4 a^2
1/4 a^2 = 81 root 3 / root 3
1/4 *a^2 = 81
a^2 = 81*4
a ^2 = 324
a = root 324
a = 18cm
Perimeter of triangle = 3*a
= 3*18
= 54 cm
Therefore, the perimeter of the equilateral triangle is 54 cm.
81 root 3 = root 3/4 a^2
1/4 a^2 = 81 root 3 / root 3
1/4 *a^2 = 81
a^2 = 81*4
a ^2 = 324
a = root 324
a = 18cm
Perimeter of triangle = 3*a
= 3*18
= 54 cm
Therefore, the perimeter of the equilateral triangle is 54 cm.
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