Question

If the area of an isosceles right angled triangle is 16 cm^2, then find the length of its hypotenuse​

Answer 1

Answer:

isoceles triangle

so,base and height will be same

let sideof triangle be x

area of triangle =16

$\frac{1}{2} {x}^{2} = 16 \\ {x}^{2} = 16 \times 2 = 32 \\ {x } = \sqrt{32} = 4 \sqrt{2}$

by Pythagoras theorem

${h}^{2} = { (4\sqrt{2} )}^{2} + {(4 \sqrt{2} ) }^{2} \\ {h}^{2} = 32 + 32 = 64 \\ h = \sqrt{64} = 8$