If the area of an isosceles right angled triangle is 32cm2, then the length of its longeest altitude is equal to
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let ABC be the Δwith AB=BC, right angled at B
∴longest altitude is basically equal to the sides of the Δ containing the 90° angle
∴longest altitude=AB=BC
ar of the Δ=32 cm²=1/2 *AB*BC=1/2*AB²
⇒AB²=64
∴AB=longest altitude=8 cm
i hope this helps!!
∴longest altitude is basically equal to the sides of the Δ containing the 90° angle
∴longest altitude=AB=BC
ar of the Δ=32 cm²=1/2 *AB*BC=1/2*AB²
⇒AB²=64
∴AB=longest altitude=8 cm
i hope this helps!!
Answered by
0
Answer:
Your questions answer is 8
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