Question

If the area of an isosceles right triangle is 8cm,what is its perimeter

Answer 1

ʜᴇʟʟᴏ ᴍᴀᴛᴇ!

Let's see what values we have!

We have a right triangle whose area is 8 cm²

Well, in right isosceles ∆ base and height are equal. Let each of them be x

8 cm² = 1/2 × x × x

16 cm² = x² or x = √16 cm² or 4 cm

Now, h² = b² + p²

h² = 4² + 4²

h = √32 cm² or 4√2 cm

Now, perimeter of isosceles ∆

= 4 cm + 4 cm + 4√2 cm

= 8 + 4√2 cm

Here, in this questio there is small error that its will be 8 cm² not 8 cm.

Hope it helps

Answer 2

Answer:

Area = 1/2bh

A=1/2x.x

8×2 =x^2

Therefore x=4

AC^2 =AB^2+BC^2

Let ac=y

y^2=4^2+4^2

y^2=16 +16

y=4√2

Perimeter= sum of all sides

4+4+4√2

=8+4√2

Step-by-step explanation: