Question

If the area of an isosceles triangle is 60 cm2 and the length of each of its equal
sides is 13 cm, find its base.​

Answer 1

Answer:

(I have also calculated the height along with the base)

ΔABC is isosceles

AB = AC =13cm

Lets drop a perpendicular AD from A to BC with height h

Let CD = x

Area of ΔADC = 1/2(xh)

Area of ΔABC = xh = 60

h = 60/x

In ΔADC by pythagoras theorem

13 square = x square + h square

Solving we get

u = 144 or 25

⇒ x = 12 or 5

CD = x

BC = 2x

⇒ BC could take two possible values 24 cm and 10 cm

Hope it helps!

Answer 2

HELLO MATE

HERE IS YOUR ANSWER

AREA OF TRIANGLE = 1/2 * B * H

60cm² = 1/2 * B * 13 cm

B = 60cm² * 2 / 13cm

B = 120/13 cm