Math, asked by noktonkonyak12, 4 months ago

if the area of an isosceless right angled traingle is 8cm2, find the equal sides. ​

Answers

Answered by snehatapadar2
1

Answer:

The area A of a triangle is 0.5(base)(height).

Since this triangle is Isosceles, the base and height are congruent.

Let x = base = height:

A = 0.5(x)(x) = 0.5x^2

Sub in the given value for area A:

8 = 0.5x^2

Multiply both sides by 2:

16 = x^2

Take the square root of both sides:

x = 4

Answered by hareeshsureshsis
0

Answer:

The area A of a triangle is 0.5(base)(height).

Step-by-step explanation:

Since this triangle is Isosceles, the base and height are congruent.

Let x = base = height:

A = 0.5(x)(x) = 0.5x^2

Sub in the given value for area A:

8 = 0.5x^2

Multiply both sides by 2:

16 = x^2

Take the square root of both sides:

x = 4

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