Question

if the area of Angle ABC is 12 square units and verticles are A (x, 2), B(4,-1)
and C (-3, 7) then find the value of x.​

Answer 1

-13 /8

Step-by-step explanation:

area=1/2*[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)]

1/2 *[x(-1-7) + 4(7-2)+ (-3)(2-(-1)) ] = 12

-8x + 20 -9 = 24=> x = - 13/8