If the area of base of cylinder is 13.86 sq. m and height is 8 m , find the lateral surface of the cylinder
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Let A and V be the base area and volume of the solid right circular cylinder respectively.
Given that the base area A=πr2=13.86sq.cm and
volume, V=πr2h=69.3
Thus, πr2h=69.3
⇒13.86×h=69.3
∴h=13.8669.3=5cm
Now the base area =πr2=13.86
722×r2=13.86
r2=13.86×227=4.41⇒r=4.41=2.1cm
Now, Curved Surface area, CSA=2πrh
=2×722×2.1×5
Thus, CSA=66sq.cm.
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