Question

If the area of circle is in ratio of 4:9. Then what is the ratio of their circumference?

Answer 1

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Answer 2

Radius of first circle = R1

Radius of second circle = R2

$\frac{area \: of \:first \: circle }{area \: of \: second \: circle} = \frac{4}{9} \\ \frac{\pi \:R {1}^{2} }{\pi \:R2² } = \frac{4}{9} \\ \frac{R1²}{R2²} = \frac{2²}{3²} \\ \frac{R1}{R2} = \frac{2}{3}$

$\frac{circumference \: of \: first \: circle }{circumference \: of \: second \: circle } = \frac{2\pi \: R1}{2\pi \: R2} \\ \\ \frac{circumference \: of \: first \: circle }{circumference \: of \: second \: circle } = \frac{r1}{r2} \\ \\ \frac{circumference \: of \: first \: circle }{circumference \: of \: second \: circle } = \frac{2}{3}$