Question

If the area of equilateral triangle is 81√3 cm^2 then find the height

Answer 1

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Answer 2

Answer:

$area \: of \: eq \: triangle = 81 \sqrt{3} {cm}^{2} \\ \frac{ \sqrt{3} }{4} {side}^{2} = 81 \sqrt{3} \\ {side}^{2} = 81 \times 4 \\ side = 18cm \\ \\ \\ height \: of \: triangle = \frac{ \sqrt{3} }{2} \times side \\ height = \frac{ \sqrt{3} }{2} \times 18 \\ height = 9 \sqrt{3} cm$

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