Question

If the area of one face of a triangular wall is

192 cm2 and its height is 12 cm, then length of its

base is​

Answer 1

Step-by-step explanation:

Area of triangular Wall = 192cm^2 192cm

2

Height = 12 cm

Base = ?

Area of traingle = 1/2 X b X h

Putting the values,

\begin{gathered} \therefore \sf 192 = \frac{1}{2} \times b \times 12 \\ \sf \implies 192 = b \times 6 \\ \sf \implies b = \frac{192}{6} \\ \sf \implies b = 32 cm \end{gathered}

∴192=

2

1

×b×12

⟹192=b×6

⟹b=

6

192

⟹b=32cm

Hence, the lenght of the base of tge triangular wall is 32 cm.

Answer 2

Given:

The area of one face of a triangular wall is  192 cm² and its height is 12 cm

To find:

The length of the bae of the wall

Solution:

Let the base of the triangular wall is = b cm

We have given the triangular wall with the height of 12 cm

and the area of it is 192 cm²

as we know that:

Area of the triangle is given by = $\frac{1}{2}.Base.Height$

now by putting the given values in the mentioned formula we get the base of the wall as:

192 = $\frac{1}{2}.b.12$

192 = $6b$

b = $\frac{192}{6}$

b = 32 cm

Hence the base of the wall is 32 cm