Question

If the area of rectangle is 128cm square and length is twice of breadth.Find it's length and breadth​

Answer 1

Given,

let length of a rectangle be = 2x

and breadth of a rectangle be = x

area of a rectangle is = 128

l×b=128

2x×x=128

2x^2=128

x^2=64

x=8

therefore the length and breadth of a rectangle are 16cm and 8cm respectively

then, perimeter of the rectangle is =2(l+b)

=2(16+8)

=2(24)

=48cm

therefore perimeter of the rectangle is 48cm

Answer 2

Given :

• Area of rectangle is 128cm².
• Length of the rectangle is twice its breadth.

To Find :

• Length and Breadth of the rectangle.

Solution :

$\longmapsto\tt{Let\:the\:breadth\:be=x}$

If length of the rectangle is twice its breadth.So ,

$\longmapsto\tt{Length\:of\:rectangle=2x}$

Using Formula :

$\longmapsto\tt\boxed{Area\:of\:Rectangle=length\times{breadth}}$

Putting Values :

$\longmapsto\tt{128=2x\times{x}}$

$\longmapsto\tt{128={2x}^{2}}$

$\longmapsto\tt{\cancel\dfrac{128}{2}={x}^{2}}$

$\longmapsto\tt{\sqrt{64}=x}$

$\longmapsto\tt\bold{x=8}$

Value of x is 8...

Therefore :

$\longmapsto\tt\bold{Length\:of\:Rectangle=8cm}$

$\longmapsto\tt{Breadth\:of\:Rectangle=2(8)}$

$\longmapsto\tt\bold{16cm}$

_______________________

VERIFICATION :

$\longmapsto\tt{Area\:of\:Rectangle=length\times{breadth}}$

$\longmapsto\tt{128=8\times{16}}$

$\longmapsto\tt\bold{128=128}$

HENCE VERIFIED