Question

if the area of rectangle is 56(x²yz+xy²z-xyz²) and it's length is 8xyz then it's breath is?​

Answer 1

Given :-

• Area of Rectangle = 56(x²yz+xy²z-xyz²).

• Length of Rectangle = 8xyz.

To Find :-

• Breadth of Rectangle.

Solution :-

Let the breadth be a.

And, We can write,

➙ Area = 56(x²yz + xy²z - xyz²)

➙ Area = 56(xyz(x) + xyz(y) - xyz(z))

➙ Area = 56xyz(x + y - z).

Now, We know that,

Area of Rectangle = Length × Breadth.

Now, Substitute the Values.

➙ 56(x²yz+xy²z-xyz²) = 8xyz × a.

➙ 56xyz(x + y - z) = 8xyz × a.

➙ a = 56xyz(x + y - z)/8xyz

➙ a = 7(x + y - z).

Therefore, Breadth of Rectangle = 7(x + y - z).