Question

If the area of rectangle is 96m² and one of it side is 8m then find its perimeter​

Answer 1

Answer:

2400.16m

Step-by-step explanation:

Length = 8 CM

Area = 96n²

unit conversion

L= 0.08m

using the formulas

A=WL

P=2(L+W)

solving for p

P= 2L+2A/L = 2.,96/0.08 = 2400.16m²

Answer 2

➤ Given :-

Area of rectangle :- 96m²

One of it's side :- 8 metres

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➤ To Find :-

The perimetre of the same rectangle.

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★ How to do :-

Here, we are given with the area of the rectangle. We are also given with one of it's side is also given to us. We are asked to find the perimetre of the same rectangle. So, first we should find the value of the other side of that rectangle by using the area and one of it's side. We can obtain with the other side. With the help of both the sides of the rectangle, we can find the perimeter of that rectangle by using the suitable formula. So, let's solve!!

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➤ Solution :-

Other side of the rectangle :-

${\tt \leadsto \underline{\boxed{\tt Area = Length \times Breadth}}}$

Substitute the given values.

${\tt \leadsto 96 = L \times 8}$

Shift thw number 96 from LHS to RHS, changing it's sign.

${\tt \leadsto L = \dfrac{96}{8}}$

Simplify the fraction to get the value of length.

${\tt \leadsto Length = \cancel \dfrac{96}{8} = 12 \: \: metres}$

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Now, we can find the perimetre of the rectangle by using the length and breadth.

Perimeter of the rectangle :-

${\tt \leadsto \underline{\boxed{\tt 2 \: (Length + Breadth)}}}$

Substitute the given values.

${\tt \leadsto 2 \: (12 + 8)}$

Add the numbers in the bracket.

${\tt \leadsto 2 \: (20) = 2 \times 20}$

Multiply the numbers to get the final answer.

${\tt \leadsto \pink{\underline{\boxed{\tt Perimeter = 40 \: \: metres}}}}$

$\Huge\therefore$ The perimeter of the rectangle is 40 metres.

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$\dashrightarrow$ Some related formulas :-

$\small\boxed{\begin{array}{cc}\large\sf\dag \: {\underline{More \: Formulae}} \\ \\ \bigstar \: \sf{{Length}_{(Rectangle)} = \dfrac{Perimetre}{2} - Breadth} \\ \\ \bigstar \: \sf{{Breadth}_{(Rectangle)} = \dfrac{Perimetre}{2} - Length} \\ \\ \bigstar \: \sf{{Length}_{(Rectangle)} = \dfrac{Area}{Breadth}} \\ \\ \bigstar \: \sf{{Breadth}_{(Rectangle)} = \dfrac{Area}{Length}}\end{array}}$