Question

If the area of rectangle is (a3+b3+c3-3abc) and the length of the rectangle is (a+b+c). Find its breadth.

Answer 1

Answer:

Step-by-step explanation:

we know that area of rectangle is lenght*breadth

and the formulae a^3 + b^3 + c^3 - 3abc = (a+b+c)(a^2 + b^2 + c^2 -ab-bc-ca )

therefore we can see that if L.H.S = area then R.H.S = L*B

so breadth = a^2 + b^2 + c^2 -ab-bc-ca

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Answer 2

Area of rectangle = L×B

or, a^3+b^3+c^3-3abc= (a+b+c) ×B

(a^3+b^3+c^3-3abc)/(a + b + c )= B

(a2 + b2 + c2 -ab - ac -bc) =B


B =( a^2+b^2+c^2 -ab-ac-bc)


so breadth of the rectangle is a^2+b^2+c^2-(ab+bc+ca)