Question

if the area of rhombus is 24 cm square and one of its diagonals is 8 cm find the perimeter of the Rhombus

Answer 1

Answer: 20

Step-by-step explanation:

Area of rhombus =1/2×d1×d2

=1/2×4×d2=24

d2=6

Perimeter = 2√d1^2+d2^2

=2√64=+36

=2√100

=2×10

=20

Answer 2

area of rhombus is equal to
half(1st diagonal * 2nd diagonal)
.
.
.
.


..

2nd diagonal is 6cm
.
.
.


diagonals of rhombus are perpendicular bisectors of each other
.....
.
.
.



therefore
by pythagoras thm
lenth of side of rhombus is 5cm
perimeter is 20cm