Question

if the area of rhombus is 24cm^2 and one of its diagonals is 4cm. find the perimeter of the rhombus

Answer 1

A = pq/2 where p and q are length of diagonals

Given:-
pq/2 = 24
pq = 48
p(4) = 48
p = 12 cm
q = 4 cm

Perimeter, P =
$2\sqrt{ {p}^{2} + {q}^{2} }$
P =
$2 \sqrt{ {12}^{2} + {4}^{2} }$
P =
$2 \sqrt{160}$