Math, asked by archnasingh405p8mf58, 1 year ago

if the area of rhombus is 96 CM square and one of its diagonal is 12 cm long find the length of the Other diagonal also find its perimeter

Answers

Answered by Anonymous
11
Area of rhombus = 1/2×d1×d2

96=1/2×12×d2

96=6×d2

d2=96/6

d2=16.

Answered by aman190k
47
Hey here is your answer
________________________

Area of rhombus = 1/2 × D1 × D2
= 96 cm^2 = 1/2 × 12 cm × D2
= (96 × 2)/12 cm = D2
= (192)/12 cm = D2
= D2 = 16 cm

As we know that diagonal of rhombus bisect
at 90°
:. In any inside triangle
8^2 + 6^2 = a^2
64 + 36 = a^2
100 = a^2
a = 10
:. Perimeter of rhombus = 4a
= 4 × 10 cm
= 40 cm
___________________________
Hope it may helpful to you
plzz mark me as brainlist
Similar questions