if the area of rhombus is 96 CM square and one of its diagonal is 12 cm long find the length of the Other diagonal also find its perimeter
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Answered by
11
Area of rhombus = 1/2×d1×d2
96=1/2×12×d2
96=6×d2
d2=96/6
d2=16.
96=1/2×12×d2
96=6×d2
d2=96/6
d2=16.
Answered by
47
Hey here is your answer
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Area of rhombus = 1/2 × D1 × D2
= 96 cm^2 = 1/2 × 12 cm × D2
= (96 × 2)/12 cm = D2
= (192)/12 cm = D2
= D2 = 16 cm
As we know that diagonal of rhombus bisect
at 90°
:. In any inside triangle
8^2 + 6^2 = a^2
64 + 36 = a^2
100 = a^2
a = 10
:. Perimeter of rhombus = 4a
= 4 × 10 cm
= 40 cm
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________________________
Area of rhombus = 1/2 × D1 × D2
= 96 cm^2 = 1/2 × 12 cm × D2
= (96 × 2)/12 cm = D2
= (192)/12 cm = D2
= D2 = 16 cm
As we know that diagonal of rhombus bisect
at 90°
:. In any inside triangle
8^2 + 6^2 = a^2
64 + 36 = a^2
100 = a^2
a = 10
:. Perimeter of rhombus = 4a
= 4 × 10 cm
= 40 cm
___________________________
Hope it may helpful to you
plzz mark me as brainlist
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