IF THE AREA OF SECTOR OF A CIRCLE BOUNDED BY AN ARC OF LENGTH 5πCM IS EQUAL TO 20πCM^2 THEN ITS RADIUS IS
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Step-by-step explanation:
Let the radius of the circle be r cm and the arc Ab of length 5π cm subtends abgle θ at the centre O of the circle. Then ,
Arc AB=5 π cm and Area of sector OAB=20 πcm2
⇒360θ×2πr=5πand360θ×πr2=20π
⇒360θ×2πr360θ×πr2=5π20π
⇒2r=4
⇒ r=8cm
We have Area = 21lr⇒20π=21×5π×r⇒r=8cm
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