Question

if the area of semicircle is 1232 CM square find the perimeter of semicircle
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Answer 1

Answer:

Step-by-step explanation:

areaof semi circular region = 1232 cm2

area of semicirlce = pi r^2/2

1232= 3.14 × r^2/2

2464 = 3.14 × r^2

784.71=r^2

r = 28.01

perimeter = pi r + 2r

= 3.14 ×28.01 + 56.02

87.9514 + 56.02

= 143.9714

perimeter = 143.9714 cm

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Step-by-step explanation:

Answer 2

Answer:

144 cm

Step-by-step explanation:

area of a semicircle =  $\frac{1}{2} \pi r^{2}$  

$1232 = \frac{1}{2} . \frac{22}{7} . r^{2}$

$1232 X 2 X 7 = 22 X r^{2}$

$\frac{17248}{22} = r^{2}$

$784 = r^{2}$

r = 28 cm

Perimeter of a semi-circle = πr + 2r

= $(\frac{22}{7} X 28) + (2 X 28)$

= (22 X 4) + (2 X 28)

= 88 + 56

= 144 cm