If the area of square is 124 m square find the perimeter
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A^2 = 124
A= √124=2√31
So perimeter is 4a =4×2√31=8√31
A= √124=2√31
So perimeter is 4a =4×2√31=8√31
Answered by
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we know that area of square =a²
a²=124
a=✓124=2✓31
perimeter of square=4a =4×2✓31=8✓31
hope it's helps
a²=124
a=✓124=2✓31
perimeter of square=4a =4×2✓31=8✓31
hope it's helps
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