Question

If the area of square is increased by 44% and the percentage increase in the perimeter is

Answer 1

Suppose the area of the square is 100 sq m. When 44% area
increased, the new area is 144 sq m. Now, the side of the
square is 12m.Side of the square is increased by 2m, which
is 20% of 10m.
perimeter is 48m. it is increased by 8 m which is 20% of 40m

Answer 2

The percentage increase in the perimeter is 20%

Step-by-step explanation:

Let the side of square be x

Area of square = $Side^2=x^2$

Perimeter of square $= 4 \times side = 4x$

The area of square is increased by 44%

Increased area = $x^2+0.44x^2=1.44x^2$

Side of new square = $\sqrt{1.44x^2}=1.2x$

Perimeter of new square = $4 \times Side = 4(1.2x)$

Difference in perimeter = 4.8x-4x=0.8x

Percentage increase in perimeter =$\frac{0.8x}{4x} \times 100 =20\%$

Hence  the percentage increase in the perimeter is 20%

#Learn more:

The perimeter of a rectangle is 100 m. If the the length is decreased by 2m and the breadth is increased by 3m, the area is increased by 44 metre square. Find the length and breadth of the rectangle

https://brainly.in/question/7583235