Question

If the area of the
largest square is 64
cm?, the side length
(in cm) of the
smallest square will
be:
4,2
2
0
2v2
4​

Answer 1

Step-by-step explanation:

Given ,

Area of square =64cm²

Find,

Length of one side of square=?

Let ,

side of square=x

Now,

Area of square = (x)²

64 =x²

x² = 64

x=√64

x=8

Hence ,

Side of square=x=8

Therefore,

Length of one side of square=8.

I hope it's help you.

Answer 2

• The side length of the smallest square will be 4 cm .

Given :- The area of the largest square is 64 cm² .

To Find :- The side length (in cm) of the smallest square will be ?

Concept / Formula used :-

• Diameter of a circle inside a square = Side of square .
• Diagonal of a square inside a circle = Diameter of circle .
• Area of a square = (side)²
• Diagonal of a square = √2 × side

Solution :-

given that,

→ Area of largest square = 64 cm²

So,

→ (Side of largest square)² = (8)²

→ Side of largest square = 8 cm

then,

→ Diameter of biggest circle inside largest square = Side of largest square = 8 cm

Now,

→ Diagonal of larger square inside biggest circle = Diameter of biggest circle = 8 cm

→ √2 × side of larger square = 8 cm

→ side of larger square = (8/√2) = (8 × √2) / (√2 × √2) = (8 × √2)/2 = 4√2 cm

using same concept again we get,

→ Diameter of bigger circle inside larger square = Side of larger square = 4√2 cm

So,

→ Diagonal of smallest square inside bigger circle = Diameter of bigger circle = 4√2 cm

then,

→ √2 × side of smallest square = 4√2

dividing by √2 both sides we get,

→ side of smallest square = 4 cm (Ans.)

Hence, the side of smallest square is equal to 4 cm .

Learn more :-

Diagonals AC and BD of quadrilateral ABCD meet at E. IF AE = 2 cm, BE = 5 cm, CE = 10 cm, 8 सेमी.

https://brainly.in/question/27312677

Let abcd be a rectangle. the perpendicular bisector of line segment bd intersect ab and bc in point e and f respectively...

https://brainly.in/question/27813873