Question

If the area of the quadrilateral EF GH is 1134 cm² and length of the diagonal EG is 54 cm. Find the length of (HG+EF)

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

The length of both the diagonals of rectangle are equal.

Hence , FH=EG

as, diagonals bisect each other

So,2(JF)=EG

2(8x+4)=(24x−8)

16x+8=24x−8

8x=16

x=2

Step-by-step explanation:

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