Question

if the area of the rectangle, 40m wide, is 2400msquare , then find its perimetre

Answer 1

Correct Question:

If the area of the rectangle and the breadth of rectangle are 2400m² and 40m. Then find it's perimeter.

Answer :-

• The perimeter of rectangle is 200m.

Step-by-step explanation:

To Find :-

• The perimeter of rectangle

Solution:

Given that,

• Area of Rectangle = 2400m²
• Breadth of rectangle = 40m

Therefore,

The length of rectangle is,

=> Length*Breadth = Area

=> Length*40 = 2400

=> Length = 2400/40

=> Length = 60

Hence, The length of rectangle is 60m. Now,

According the question,

• The perimeter of rectangle

As we know that,

Perimeter of rectangle = 2 ( Length + Breadth ),

=> 2 ( Length + Breadth )

=> 2 ( 60 + 40 )

=> 2 ( 100 )

=> 2*100

=> 200

Therefore,

• The perimeter of rectangle is 200m.

Answer 2

Step-by-step explanation:

★ Concept :-

✪ Here we use the concept of Perimeter of Rectangle. As we see, that we are given the Area and the Breadth of the Rectangle. Then firstly, we will find out the Length using the formula of Area of Rectangle. After that, by applying the required values in the formula of Perimeter of Rectangle we will get the answer.

Let's do it !!!

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★ Formula Used :-

$\star\;\underline{\boxed{\sf{\pink{Area\ of\ Rectangle\ =\ \bf length \times breadth.}}}}$

$\star\;\underline{\boxed{\sf{\pink{Perimeter\ of\ Rectangle\ =\ \bf 2(length\ +\ breadth).}}}}$

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★ Solution :-

Given,

↠Area of Rectangle = 2400m².

↠Breadth of Rectangle = 40m.

------------------------------------------------------------

~ For the length of rectangle ::

➷ We know that,

$\sf \rightarrow {Area\ of\ Rectangle\ =\ \bf length \times breadth}$

⦾ By applying the values, we get :-

$\sf \rightarrow {Area\ of\ Rectangle\ =\ \bf length \times breadth}$

$\sf \rightarrow {2400\ =\ \bf length \times 40}$

$\sf \rightarrow {\cancel \dfrac{2400}{40}\ =\ \bf length}$

$\sf \rightarrow {60\ =\ \bf length}$

$\bf \rightarrow {Length\ =\ {\red {60m.}}}$

∴ Hence, length of rectangle = 60m.

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~ For the perimeter of rectangle ::

➷ We know that,

$\sf \mapsto {Perimeter\ of\ Rectangle\ =\ \bf 2(length\ +\ breadth)}$

⦾ By applying the values, we get :-

$\sf \mapsto {Perimeter\ of\ Rectangle\ =\ \bf 2(length\ +\ breadth)}$

$\sf \mapsto {Perimeter\ of\ Rectangle\ =\ \bf 2(60\ +\ 40)}$

$\sf \mapsto {Perimeter\ of\ Rectangle\ =\ \bf 2(100)}$

$\sf \mapsto {Perimeter\ of\ Rectangle\ =\ \bf 2 \times 100}$

$\bf \mapsto {Perimeter\ of\ Rectangle\ =\ {\orange {200m.}}}$

∴ Hence, perimeter of rectangle = 200m.

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★ More to know :-

➸ The opposite sides are parallel and equal to each other.

➸ Each interior angle is equal to 90°.

➸ The sum of all the interior angles is equal to 360°.

➸ The diagonals bisect each other.

➸ Both the diagonals have the same length.

➸ Diagonal of rectangle = √l² + b².