Question

If the area of the rectangle ABCD is 45cm² find the area of △BCE?​

Answer 1

Given ABCD is parallelogram.

Let the diagonal BD divides parallelogram ABCD into 2 triangles.

i.e., Δ ABD; Δ BCD

Area of ABD+ Area of BCD

=Area of ABCD

∵ ABD=BCD

∴2(Area of BCD)= Area of ABCD ……….(1)

'E' is M.P of BC, so DE divides Δ BCD into 2 equal triangles

i.e., ΔBED & Δ DEC

Area of ΔBCD= Area of ΔBED+ Area of Δ DEC.

Area of ΔBCD=2(Area of ΔDEC)

By (1)

2[2(Area of DEC)]= Area of parallelogram ABCD

4(Area of DEC)=Area of ABCD

∴ Area of ΔDEC=

4

1

(Area of parallelogram ABCD).

solution