Question

If the area of the rectangle is 4x² + 4x – 3, then find its possible dimensions​

Answer 1

Answer:

If the area of a rectangle is 4x2 + 4x - 3, then its possible dimensions are: 2x - 3, 2x + 1.

Answer 2

Given:

The area of the rectangle is 4x² + 4x – 3,

Solution:

Know that,

Area of rectangle $\[ = {\rm{length}} \times {\rm{breadth}}\]$

Factorize, $\[4{x^2} + 4x - 3\]$

$\[\begin{array}{l} = 4{x^2} + 6x - 2x - 3\\ = 2x\left( {2x + 3} \right) - 1\left( {2x + 3} \right)\\ = \left( {2x + 3} \right)\left( {2x - 1} \right)\end{array}\]$

Hence, The possible dimension are $\[\left( {2x + 3} \right)\left( {2x - 1} \right)\]$,