Question

If the area of the rectangle is128cm2 and length and length is twice to breadth.find the length and breadth
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Answer 1

Answer:

The answer will be :

Length = 8cm;

Breadth = 4cm;

Step-by-step explanation:

Given that ;

         area = 128 cm^2;

 Let, breadth be b;

Then,              l = 2b;

Now area of a rectangle = l * b;

 Now, put all value inside the formula;

                    l * b = 128;

                    l * (2l) = 128;

                   2l^2 = 128;

                     l^2 = 128 / 2;

                      l^2 = 64;

                       l = 8;

• Hence, length = 8cm;

2( breadth )= length

Breadth = length / 2;

breadth = 8 / 2;

• Breadth = 4cm;

That's all.

Answer 2

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ANSWER :

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The Breadth of the rectangle = b

The Length of the rectangle, l = 2b

The Area of the Rectangle, A = 128 cm^2

We know that ,

$area \: of \: rectangle \: = l \times b$

From this ,,,

Area , A = 2b × b

128 = 2b^2

b^2 = 64

b = 8 cm

The Length of Rectangle, l = 2b

l = 2 × 8

l = 16 cm

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