if the area of the similar triangle are equal. prove that they are congruent
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ayush794:
where is proof
It is on the next picture
There are 3 photos
did u got?
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Not necessarily.
We all know that the area of a triangle is equal to its base multiplied by half its height (a = 1/2 bh) .
So for example, the area of two different triangles is 24 sq cm.
The length of the base and height of one triangle could be 4 and 12, while the length of the base and height of another triangle could be 6 and 8.
And if this should be true, then triangles with disproportionate lengths can not be congruent.
However, if the two triangles happen to be equilateral, then they would be congruent because each of their side lengths can only be one number.
HOPE IT HELPSS U
We all know that the area of a triangle is equal to its base multiplied by half its height (a = 1/2 bh) .
So for example, the area of two different triangles is 24 sq cm.
The length of the base and height of one triangle could be 4 and 12, while the length of the base and height of another triangle could be 6 and 8.
And if this should be true, then triangles with disproportionate lengths can not be congruent.
However, if the two triangles happen to be equilateral, then they would be congruent because each of their side lengths can only be one number.
HOPE IT HELPSS U
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