Question

If the area of ​​the square increases by 20%, how much will the arm increase​

Answer 1

Step-by-step explanation:

let initial length of arm be x

So x^2 = 100% (1)

now the area is increased by 20%

new area = 120%

(new arm length)^2 = 120

new arm length = √120 = 2√30 = 10.95 ~ 11

So % increase in the length of arm = (11-10)/10 x 100 = 10%

OR without rounding we get (10.95 - 10)/10 x 100 = 9.5% increase