Question

if the area of the square is (X²+6x+9)units find its side ​

Answer 1

$area \: of \: square \: = {x}^{2} + 6x + 9$

$(side) {}^{2} = {x}^{2} + 6x + 9$

$(x + y) {}^{2} = {x}^{2} + 2xy + {y}^{2}$

${(side)}^{2} = {(x)}^{2} + 2(3)(x) + {(3)}^{2}$

$\: \: \: \: \: \: \: \: {(side)}^{2} = (x + 3) {}^{2}$

$\: \: \: \: \: \: \: \: \: \: \: \: side \: = x + 3$

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