Question

if the area of the trapezium whose parallel sides are 6cm and 10 cm is 32cm^2 then the distance between the parallel sides is?​

Answer 1

Answer:

h =4

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Answer 2

We know,

Area of trapezium = ½ × (sum of parallel sides) × (distance between parallel sides)

Then,

$\tt32 = \frac{1}{2} \times (6 + 10)(distance \: \: between \: \: parallel \: \: sides) \\ \\ \rm distance \: \: between \: \: parallel \: \: sides = \frac{32}{ \frac{1}{2} } \times \frac{1}{6 + 10} \\ \\ \mapsto \frac{32 \times 2}{16} \: \: \: \: = \sf\red4 \:\: cm$