Question

If the area of the triangle formed by the
lines.x=0, y=0,3x+4y=a. (a>0) is 1, then a
​

Answer 1

Answer:

Given that,

X=0,y=0

3x+4y-a=0_________(1)

A=3,B=4,C=-a

C square /2labl=6

A2/2l3.4l =6

Therefore a square =144

A=12

Answer 2

Answer: The value of a = 2√6 or 4.8989

Step-by-step explanation:

Given

• 3x+4y=a
• a > 0
• x=0, y=0
• Area of triangle = 1

To find:

• Value of a.

Calculations:

      3x+4y=a

Dividing the given equation by a.

     3x/a +  4y/a = a/a

  → x/(a/3)+y/(a/4) = 1

• The intercept of x =a/3.
• The intercept of y =a/4

Area of triangle = 1/2 x base x height

                           = 1/2 x a/3 x a/4.

According to the question,

  1/2 x a/3 x a/4 = 1

       a²/24 = 1

      a² = 1 x 24

      a² = 24

      a = 2√6

      a = 4.8989.

Final answer :

The value of a = 2√6 or 4.8989.

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