Question

if the area of the triangle formed by the points (k,0),(3,4),(5,-2) is 10sq.units,then find k.​

Answer 1

Answer:

Step-by-step explanation:

A(K,0) B(3,4) C(5,-2)

area of ABC=(K(4+2)+3 (-2-0)+5 (0-4)

10 =(K(6)+3 (-2)+5 (-4)

10 =(6K-6-20)

10 =6K-26

10+26=6K

36=6K

K=6

Answer 2

Answer:

The value of $k=6$

Step-by-step explanation:

We are given that the area of triangle is $10$sq units.

The area is formed by three points.

Points are $(k,0),(3,4),(5,-2)$.

A triangle is defined as a three-sided polygon that is composed of three edges and three vertices.

The sum of the internal angles of a triangle is equal to $180$ degrees. It is called angle sum property of a triangle.

Here, the area can be calculated as:

area of triangle=$(k(4+2)+3 (-2-0)+5 (0-4))$

$10 =(k(6)+3 (-2)+5 (-4)$

$10 =(6k-6-20)$

$10 =6k-26$

$10+26=6k$

$36=6k$

$k=6$

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