Question

If the area of trapezium is 172 Square Cm and parallel sides are 25 Cm and 18 Cm. Then height will be

Answer 1

Answer:

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Step-by-step explanation:

Continued….

∆ADP is right angled triangle

AD = 25 cm, DP = 15 cm, AP is altitude or perpendicula height.

AD^2 = DP^2 + AP^2 (Pythagoras theorem)

25^2= 15^2+ AP^2

25^2–15^2= AP^2

(25+15)(25–15) = AP^2

40*10= AP^2

400= AP^2

+or-20 = Ap ( taking sq.root on both sides)

AP = +20

Area of trapezium ABCD = 1/2(sum of the two parallel sides *height )

= (1/2)(40+10)*20

(1/2)*1000= 500 sq.cm