Math, asked by Anonymous, 8 months ago

If the area of trapezium with parallel sides of lengths 30cm and 23cm respectively is 265sq cm, what is its height? ​

Answers

Answered by supernovalegend
1

Answer:

10 cm

Step-by-step explanation:

The area of trapezium = \frac{1}{2}× sum of parallel sides × height

            265    =       \frac{1}{2}  × 30+23 × h

            265 =  \frac{1}{2} × 53×h  ⇒  h =\frac{265 x 2}{53}

                                                =\frac{530}{53}

                                     Height = 10 cm

Answered by Anonymous
3

Answer:

hilu ❤️

Step-by-step explanation:

refer to the attachment pls ❤️

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