if the area of triangle A(a,2a) B(-2,6) C(3,1) is 10 sq.units find a
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x1 = a x2 = -2 x3 = 3
y1 = 2a y2 = 6 y3 = 1
formula time!
1/2 { a+(6-1) + -2 ( 1- 2a) + 3 ( 2a - 6)} = 10
1/2 { 6a -a -2 + 4a + 6a -18 } = 10
1/2 { 15 a - 20 } = 10
taking 1/2 to the other side
15 a - 20 = 20
a = 40 / 15 = 8/3
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