Question

If the area of triangle A, with sides of 6, 8, and 10, equals the area of rectangle B, with width of 4, what is the perimeter of the rectangle?

Answer 1

$area \: of \: traingle = \sqrt{}s \: (s - a)(s - b)(s - c) \\ \sqrt{} 12(12 - 10)(12 - 8)(12 - 6) \\ \sqrt{} 12 \times 2 \times 4 \times 6 \\ \sqrt{} 24 \times 24 \\ 24.$

$area \: of \: rectangle = (l \times b) \\ 24 = l \times 4 \\ l = 6$

$perimeter \: of \: rectangle = 2(l + b) \\ 2 \times( 6 + 4) \\ 20.$