Question

If the area of triangle ABC is 9 CM square and area of triangle is 64 CM square , DE= 5.1 cm find AB​

Answer 1

You forgot to include that the triangles are similar

let ∆ABC ~ ∆DEF

We know that the ratio of the areas of two similar triangles is equal to the ratio of the square of their corresponding sides

$\frac{Ar(ABC)}{Ar(DEF)}$ = $(\frac{AB}{DE})^2$

=> $\frac{9}{64}$ = $(\frac{AB}{DE})^2$

=> $\sqrt{\frac{9}{64}}$ = $\frac{AB}{DE}$

=> $\frac{AB}{5.1}$ = $\frac{3}{8}$

=> 8AB = 3 × 5.1

=> AB = 1.9125

Answer 2

Hey mate hope it helps u.......