if the area of triangle AMB is 30 square cm.find the area of triangle AMC. mis the mid point
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Area of ∆AMC = 30 cm^2.
Step-by-step explanation:
If M is the mid point of ∆ABC, then the area of
∆AMB and ∆AMC will be equal.
∆s having common vertex, ratio of areas of two ∆s will be equal to the ratio of length of there bases.
Here, M is the mid-point of BC, so, BM = MC.
Hence, the area of ∆AMC = 30 cm^2.
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