Math, asked by sathyacs, 11 months ago

if the area of triangle is 3 sq. Units, whose vertices are (1,3)(0,0)and (k,0).​

Answers

Answered by nandampranith
5

Answer:

2

Step-by-step explanation:

by using area of triangle formula

1/2 |x1(y2-y3)+x2(y3-y1)+x3(y1-y2)|=area of triangle

by submit the values we get k=2

Answered by NehaKari
1

Given:

The area of triangle is 3 sq. Units. whose vertices are (1,3) (0,0) and (k,0).​

To Find:

Value of k.

Solution:

We know are of triangle is

= (1/2) [x₁ (y₂ – y₃ ) + x₂ (y₃ – y₁) + x₃(y₁ – y₂)]

put value in above equation

3 = 1/2 [1 (0-0) + 0(0-3) + k(3-0)]

6 = [3k]

k = 6/3

k = 2

Hence, the value of k is 2.

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