if the area of triangle is 3 sq. Units, whose vertices are (1,3)(0,0)and (k,0).
Answers
Answered by
5
Answer:
2
Step-by-step explanation:
by using area of triangle formula
1/2 |x1(y2-y3)+x2(y3-y1)+x3(y1-y2)|=area of triangle
by submit the values we get k=2
Answered by
1
Given:
The area of triangle is 3 sq. Units. whose vertices are (1,3) (0,0) and (k,0).
To Find:
Value of k.
Solution:
We know are of triangle is
= (1/2) [x₁ (y₂ – y₃ ) + x₂ (y₃ – y₁) + x₃(y₁ – y₂)]
put value in above equation
3 = 1/2 [1 (0-0) + 0(0-3) + k(3-0)]
6 = [3k]
k = 6/3
k = 2
Hence, the value of k is 2.
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