If the area of triangle with vertices (x, 3), (4, 4) and (3, 5) is 4 square units, find x.
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Answered by
0
In Heron's formula, s is the semi-perimeter (one-half the perimeter of the triangle).
s = 1/2 ( a + b + c )
Area = sqrt ( s ( s-a) ( s-b) ( s-c) )
Therefore ,
⇒ ½[x(4 – 5) + 4(5 – 3) + 3(3 – 4)] = 4
⇒ (–x + 5) = 8
⇒ x = –3
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Refer to the attachment!!^^
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