If the area of triangle with vertices (x, 3), (4, 4) and (3, 5) is 4 square units, find x.
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Ar (∆ABC) = 4
⇒ ½[x(4 – 5) + 4(5 – 3) + 3(3 – 4)] = 4
⇒ (–x + 5) = 8
⇒ x = –3
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