if the area of triangle with vertices0,0 1,6 0,a find the value ofa
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Area of triangle =
2
1
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
x
1
0
0
1
2
1
1
1
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
=4
⇒∣x(1−2)−1(0−2)+0∣=8
⇒∣−x+2∣=∣x−2∣=8
⇒x−2=±8⇒x=±8+2=−6,10
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