If the area of two similar are equal draw that they are congrant? Ans of that question plzz
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yes, they are congruent
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Heyo !!
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Given :- Two ∆s ABC and PQR such that ∆ABC ~ ∆PQR and ar(∆ABC) = ar(∆PQR)
To prove :- ∆ABC ≈ ∆PQR
Proof :- ∆ABC ~ ∆PQR
angle A = angel P , angle B = angle Q and angle C = angle R
and AB/PQ = BC/QR = AC/PR
Now, ar(∆ABC) = ar(∆PQR)
ar(∆ABC) / ar(∆PQR) = 1
=> (AB/PQ)² = (BC/QR)² = (AC/PR)² = 1
=> AB/PQ = BC/QR = AC/PR = 1
AB = PQ , BC = QR and AC = PR
Therefore, ∆ABC ≈ ∆PQR
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Given :- Two ∆s ABC and PQR such that ∆ABC ~ ∆PQR and ar(∆ABC) = ar(∆PQR)
To prove :- ∆ABC ≈ ∆PQR
Proof :- ∆ABC ~ ∆PQR
angle A = angel P , angle B = angle Q and angle C = angle R
and AB/PQ = BC/QR = AC/PR
Now, ar(∆ABC) = ar(∆PQR)
ar(∆ABC) / ar(∆PQR) = 1
=> (AB/PQ)² = (BC/QR)² = (AC/PR)² = 1
=> AB/PQ = BC/QR = AC/PR = 1
AB = PQ , BC = QR and AC = PR
Therefore, ∆ABC ≈ ∆PQR
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