if the area of two similar triangles are 162sqcm and 200sqcm respectively find the ratio of their perimeters
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Answer:
162sqcm=54+54+54
200sqcm=60+70+70
Step-by-step explanation:
162sqcm= I divide it by three then it equals to 54 . so 54+54+54
200sqcm= I subtract with 60 then it equals to 140, 140 I divide it by 2 becomes70. So 60+70+70
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