Question

if the area of two squares is 9 sq. cm and 16 sq.cm respectively. what will be the perimeter of the square whose area is equal to the sum of the areas of these two squares?​

Answer 1

Answer:

perimeter of square is 20cm

Step-by-step explanation:

area of square A = 9$cm^2$ = $side^2$

area of square B = 16$cm^2$

so side of square A = 3cm

side of square B = 4cm

area of another square C = area of square A + area of square B

area of another square C = 9 + 16 = 25$cm^2$

side of square C is 5cm

perimeter of square C is 4(side)

perimeter = 4(5) = 20 cm

Answer 2

Answer:

 perimeter of the square is 20 cm  

Step-by-step explanation:

Given that areas of the 2 square = 9 sq and 16 sq

           sum of the two squares area  =9+ 1 6 = 25 sq

      area of the square   $a^{2}$ = 25 sq  ( here a is side of the square)

                                     $a$ × $a$ = 5× 5  ( 5× 5 = 25)

               there fore side of the square $a$ = 5 cm

                     perimeter of the square = 4 × side of the square

                                                               = 4 $a$

                                                                = 4× 5 = 20 cm