Question

If the area pf rectangle is 4x3+4x-3 then its possible dimensions are

Answer 1

sᴏʟᴜᴛɪᴏɴ :-

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ᴛᴏ ᴋɴᴏᴡ ᴛʜᴇ ᴅɪᴍᴇɴsɪᴏɴs, ᴡᴇ ʜᴀᴠᴇ ᴛᴏ ғᴀᴄᴛᴏʀɪsᴇ ᴛʜᴇ ᴀʀᴇᴀ ɪ. ᴇ. 4x^2 + 4x - 3

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ғᴀᴄᴛᴏʀɪᴢᴀᴛɪᴏɴ :- 4x^2 + 4x - 3

=> 4x^2 - 2x + 6x - 3

=> 2x ( 2x - 1 ) +2 ( 2x - 1 )

=> ( 2x + 2 ) ( 2x - 1 )

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Ⓓⓘⓜⓔⓝⓢⓘⓞⓝ => (2x+2) and (2x-1)

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#Ayush1abhigyan

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Answer 2

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Formula for Area of Rectangle =

L X B

Area of the given rectangle = $4x^{3} + 4x - 3$

So, $4x^{3} + 4x - 3 = L \times B$

To find the dimensions, we have to factorise the given area,

$4 {x}^{2} + 4x - 3 \\ = > 4 {x}^{2} - 2x + 6x - 3 \\ = > 2x(2x - 1) + 2(2x - 1) \\ = > (2x + 2)(2x - 1)$

On, factorising we get, the dimensions

L = $\bold{(2x+2)}$

B = $\bold{(2x - 1)}$