If the areas of circular bases of a frustum of a cone are 4 cm.sq and 9 cm.sq respectively and
the height of the frustum is 12 cm. What is the volume of the frustum?... PLZ ANSWER IT FAST.... I WILL MARK IT AS BRAINLIEST.
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Answer:
Height=12
Volume of frustum=1/3h√A1+A2+√A1×A2
=1/3×12√4+9+√4×9
=4√13+6
=4√19 cm³
satgupta23:
Agar ye formual h... To bhi ans galat h... Shi ans 44 h.. Rd h to dekh lo.. But i want method..
Hey there is some mistake in formula .
Volume=A1+A2+√A1×A2
Whole square root was not there
Then answer is 76cm³
Thanx bhai.. Mera bhi yhi ans aa rha tha... Lekin RD mein ans 44 diya h.. Isliye mujhe doubt hua tha... Par tumhara bhi yhi aaya.. So thnxx
I am not bhai
I am a girl student
Oh.. Then sorry behen
It's ok bhaiya
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