Question

If the areas of circular bases of a frustum of a cone are 4 cm² and 9 cm² respectively and the height of the frustum is 12 cm. What is the volume of the frustum?

Answer 1

Answer:

The Volume of frustum of a cone is 76 cm³.

Step-by-step explanation:

Given :  

Areas of the circular bases of a frustum of a cone are 4 cm² and 9 cm² i.e  

A1 = 9 cm² , A2 = 4 cm²

Height of the Frustum ,h = 12 cm

Volume of frustum of a cone, V = h/3 [A1 + A2 + √(A1 ×A2)]

V = 12/3 [(9 + 4) + √(9 × 4)]

V = 4 [13 + √36]

V = 4 [13 + 6]

V = 4 × 19

Volume of frustum of a cone = 76 cm³

Hence, the Volume of frustum of a cone is 76 cm³.

HOPE THIS ANSWER WILL HELP YOU ..

Answer 2

Here Is Your Ans ⤵

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➡Volume of frustum = H / 3 ( A1 + A2 + √A1×A2 )

➡Volume of frustum = 12 / 3 ( 4 + 9 + √4 × 9 )

➡Volume of frustum = 4 (13 + √36)

➡Volume of frustum = 4 (13 + 6)

➡Volume of frustum = 76 cm³

Hence , 76 Cm³ is the volume of the frustum

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